The Three
Bears
Just then,
Goldilocks woke up
Broke up the party and beat it out there
Bye-bye, bye, bye, said the daddy bear
Goodbye, bye, said the mamma bear
Hey bubba-rebear, said the wee bear
So ends the story of the three bears
So, don't
forget children, whatever you do
Don't go down to the woods tonight
Because the bears'll get ya!
Never mind
Goldilocks and the Three Bears, what about Absolute and The Three Zeroes.
In a previous blog post I proposed that there are three
zeros: 1) absolute zero, 2) relative zero and 3) repeating zero. If one of the
four cells in an outcome matrix is an absolute, then the other three cells must
be zero if the entire outcome matrix is also to be absolute. Let’s assume the
rows of the outcome matrix are wins and losses and the columns of the outcome matrix
are true and false. Then if any of those four cells are absolute then the other three
cells must be one of the three zeroes.
If Quadrant I ( Quadrant numbering follows standard mathematical conventions: Top Right is Quadrant I, Top left is Quadrant II, bottom left is Quadrant III and bottom right is Quadrant IV) of the outcome matrix are true wins, then Quadrant
II are false wins, Quadrant III are false losses and Quadrant IV are true losses. the outcome matrix
is certain if all four cells sum to 100% and the outcome matrix is an absolute
when any one of the four cells is 100%. If the absolute is a true win, then Quadrant 2 must also be a False Win and an absolute zero; Quadrant III must be a False Loss and a relative zero, and Quadrant
I must be a True Loss and a repeating zero. An absolute win is identical with an
absolute loss. However an absolute win does not also have to be true. It is
only true if the members of the group are also true. If there are N members of
a group then if a group is going to function as an absolute, then N must be equal
to three ( if N→∞ is 1, 100%, then Quadrant II is N/3 according to L’Hôpital’s Rule.)
If the outcome matrix is to be certain AND true,
then the Quadrant I must be N/3, and the sum of Quadrant I and Quadrant III
must also be true. This makes the zero
in Quadrant III an absolute zero. The zero in Quadrant IV, a False Win, must be
a relative zero since it is offset from an absolute zero. This means that the
zero in Quadrant II, a False Loss, must be a repeating zero. Thus there are four
outcomes if an absolute is certain: Absolutely true; absolutely false; absolutely
a win, and absolutely a loss.. If the absolute must be certain and true
, then there is only one matrix that satisfies
this and as stated previously, Quadrant I must be N/3. If all cells of the outcome
matrix must also be between zero and one, then non-negative values can be found
for Quadrants II, III and IV that can satisfy the certainty of the outcome matrix
if the members of the group are greater than 3. If the number in the group is 3,
it IS consistent with the absolute. If N,
the members of the group, is only 1 there are NO non-negative values of Quadrants
I, II, and IV that can e found that are also true. If the number of members of a Group are 2 and
Quadrant II is zero, then the group can be true OR false depending on the values
for False Wins and False Losses. If the value of False Losses is between
zero and 1/6 and the value of False Wins is also between zero and 1/6, and the value of False Losses plus False Wins
is equal to 1/3 then the group is true. To satisfy both conditions, if N=2, only
Quadrant II=Quadrant IV=1/6 is possible. This means that the sum of values in Quadrant
II and IV, which remember is only the stand-in for ties, is a normal distribution. Otherwise the win is ABnormal. If the percentage of True
wins is 2/3, 66 2/3%, and the sum of False Wins plus False Losses, i.e. ties, follow a normal distribution. The maximum positive normal skew is 96%, the False Wins are 2% and the False Losses are also 2%. The minimum normal skew would be 46.53% and the False Wins and False Losses would
be each 26.785%. However any value for False Wins less than 25% is also certainly false. This means that 91%
of the normally distributed values with a Quadrant II of 2/3 are true and 9%
are false.
An absolute appears consistent with groups with three Members,
a trinity. A group with more than three members can always be true, a group
with only 1 Member will always be false. Groups with two Members can be either true
OR false. Groups with two Members (for example a two party systems according to Duverger’s Law), which
are normally distributed with a location parameter of 2/3 and a range parameter
equal to ½ are true 91% of the time, including all those that are positively skewed,
but are false 9% of the time, including the maximum negative normal skew.
A normal win in a real election with two group (e.g. parties)
indicates that the win is true 91% of the time. If the distribution of False Wins
and False Losses (whose sum is ties) are normally distributed, it will be false
9% of the time including some negatively skewed normal distributions. The maximum
positive skewed normal distribution for a group of two has a win certainty of
98%, and a truth certainty of 96%, That is almost identical to the absolute value of
100%.
Things that are assumed in making wins true.
1 The members of the group should approach the absolute, i.e.,
N→∞. All measures that decrease N, such as voter suppression, reduce the chances
of the win being true.
2. Ties have to be
allowed. Zero-sum games assume than a contest will always result in a win and that
all other outcomes are a loss. Thus contests that include a fixed sum, such as fixing
the size of the House at 435 seats, the number of Supreme Court justices at 9,
or fixing the currency to a commodity standard, should not be allowed. It is
noted that if rather than the current method of allocating Congressional House
seats, a method which apportions of one seat to the smallest state by population
and all other seats based on the ratio to that state, currently Wyoming. This is
why the popular name for this rule is the “Wyoming” rule.
3. There must be
three choices accommodating the three outcomes of win, loss, and tie. Since Duverger’s
Law says that in the current single representative for a district system used
in the United States will tend to two parties (groups) , this can be satisfied if
each of the two parties nominates two candidates in each election. Otherwise
voting might only indicates opposition to a candidate, not voting for a
candidate.
4. Rank choice voting, as currently used in Alaska, should
be include in all elections where the winner is by plurality rather than majority.
In the 2024 Presidential election, at least the state votes in Michigan (Trump
49.7%) and Wisconsin ( Trump 49.6%) were by less than a 50% majority.
5. The electoral college is intended to elect a President based
on the people’s choice AND the state’s choice. Thus awarding electoral votes
should be done by Congressional District AND by states, as is the case currently
only in Nebraska and Maine. It is not commonly reported what the people’s portion of electoral
college vote would have been in all other states if they were awarded by Congressional
House District.
Even if all of these measures were in effect, it is noted
that a normal election with two major parties is only absolutely true in 91% of
all cases, based on statistics and game theory. Knowing the difference in the
three zeroes makes it possible to solve for truth even when some of the Quadrants
are NOT zero. And it in reality, where there are both, 2, sides not being normal is not being truthful.