Red Rubber
Ball
And I think it's gonna be all rightYeah, the worst is over now
The mornin' sun is shinin' like a red rubber ball
But how does
that red rubber ball
bounce?
A bounce, rebound, occurs when an object, such as a particle,
encounters a discontinuity. That discontinuity can be a physical surface, or it
can be merely observational, that is the ability to observe, and measure, may
be the actual reason that there appears to be a discontinuity..
If a particle is moving, and is not acted upon by a force,
that particle moves in a straight line. That is Newton’s Law of Inertia. However
this is only true if space is flat. It is more proper to say that a particle
moves along the geodesic in its space. If the space is flat, then the geodesic is
a straight line. But if that space is not flat, for instance is spherical or hyperbolic,
then it is non-Euclidean, and only flat space is Euclidean.
We say that the Earth is a sphere, and we live on the Earth’s
spherical surface. That is why the shortest distance between two points on earth
is more properly a Great Circle Distance. While this is true, it might be only
of interest to airplane pilots and others who measure vast distances. When the
distances involved are far less than the radius of the Earth, then the solution
for the hypotenuse of a triangle on that spherical surface is cos(c/R)=cos(a/R)*cos(b/R),
where R is the radius of the Earth/spherical surface, and it is virtually
identical to the solution on a classical flat Euclidean surface, cos(c)=cos(a)*cos(b),
as can be verified by using the series for the trigonometric functions. Both of
these are equal to Pythagoras’ Theorem, c=√(a2+b2).
It is therefore customary to say that the distances on Earth are spherical globally but are flat locally.
Might this also be true for space?
The solution for the hypotenuse of a triangle on a hyperbolic
surface uses hyperbolic trigonometric functions, cosh(c)=cosh(a)*cosh(b).
This has a different solution than the classical solution. The classical solution
relies on the circular identity, cos2+sin2=1. In hyperbolic space the identity cosh2-sinh2=1
applies. Additionally space may not be merely what can be observed, it might be
that which can not be observed, i. In this case reality having a coefficient
of zero for that which can not be observed can be expressed as a complex number
which is reality plus zero imagination, r+0*i. If reality is the solution
of a triangle r2=(a2+b2)+02*i,
then its solution in hyperbolic space is
ln(cosh(√(a2+b2)) ± sinh(√(a2+b2))) because cosh(02) is 1, where the
± indicates that there are
two solutions. Because cosh is symmetrical while sin is symmetrical, and for small values of a2+b2 compared to the size of the universe, sinh(√(a2+b2)), the uncertainty, is also small. This
can be also expressed as a single solution, ln(cosh(√(a2+b2))-sinh(√(a2+b2))), if reality is one solution. This is no different than electrical engineering where
some solutions have real and imaginary components, and the imaginary component
is ignored. The single solution merely says that the real solution has the opposite
sign of the imaginary solution, and that the imaginary solution is being
ignored.
A rebound in flat space is symmetrical because a straight line
is symmetrical about that discontinuity. Hyperbolic motions are NOT symmetrical
as real numbers. They are almost linear on one side of the discontinuity and
almost parabolic on the other side of the discontinuity. If there is a linear
motion on one side of a discontinuity and that discontinuity is NOT a surface
and the motion is parabolic on the other side of the discontinuity, this probably
is an indication that the motion is hyperbolic, NOT a highly skewed parabola. A
parabola requires an imaginary solution if that motion passes through, is rotated
by 180º or π. It is suggested that is more reasonable to assume that this
discontinuity is because the observable behavior continues as unobservable behavior
than it is to assume the behavior has become imaginary.
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